Algebra II · 35 minutes
Suggested grades 10–12 · Unit 2: Complex solutions and exponential models · Lesson 1 of 2
Quadratics with Complex Solutions
Extend square-root reasoning beyond real-number solutions.
Mr. S Teaches · Original starter lesson · HS-ALG2-03 · Grade range is planning guidance.Watch, notice, discuss
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Quadratic Equations with Complex Solutions: Intro
By Euler's Academy
Introduce complex roots and the absence of real x-intercepts; substitute a result back into the equation.
Open on YouTube: Quadratic Equations with Complex Solutions: Intro (opens a new tab) ↗How To Solve Quadratic Equations Using The Quadratic Formula
By The Organic Chemistry Tutor
Review the formula as the solving tool; extend a negative discriminant using i in the lesson.
Open on YouTube: How To Solve Quadratic Equations Using The Quadratic Formula (opens a new tab) ↗What does a negative discriminant tell you, and how can you verify a complex root?
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Learning objective
Solve real-coefficient quadratic equations with complex roots and verify a result.
Before you begin
- Completing the square
- Square roots
Gather your materials
- Paper and pencil
- Graph paper
- Calculator for checking results
Language to know
- imaginary unit
- The number i defined by i²=−1.
- complex number
- A number a+bi with real a and b.
- conjugate pair
- Numbers a+bi and a−bi.
Understand the concept
A negative square is impossible for a real number, but the complex system includes i with i²=−1. Solving (x−2)²=−9 gives x−2=±3i rather than “no solution” without qualification. “No real solution” and “no complex solution” are different claims. Real-coefficient quadratics produce conjugate nonreal roots.
Teach it step by step
- Solve x²−4x+13=0 by completing the square: (x−2)²=−9.
- Use i²=−1 to express both square roots of −9.
- Write x=2±3i and verify one root by substitution or the completed-square form.
- Compare with x²−4x−5=0 to distinguish negative and positive discriminant situations.
Make the thinking visible
Worked example or model response
For x=2+3i, (x−2)²=(3i)²=−9, so the completed-square equation holds. The other root is 2−3i. In contrast x²−4x−5=(x−5)(x+1), with real roots 5 and−1.
Guided practice
Solve (x+1)²=−16 and verify one candidate.
Independent practice
1. Solve x²+6x+13=0. 2. Solve 2x²+8=0. 3. Explain the phrase “no real roots” for x²+1=0.
Quick assessment
Why is √(−9) represented by 3i rather than−3?
Answer key & assessment criteria
Answers and teaching guidance
- Guided: x=−1±4i; squaring x+1 gives−16.
- Independent 1:(x+3)²=−4, roots−3±2i. 2: x²=−4, roots±2i. 3: The complex roots are±i, but neither is real.
- Quick check:(−3)²=9, whereas (3i)²=−9.
Look for: Require the learner to explain the interpretation and check, not only state a result. Distinguish an exact value from a rounded approximation and attend to the stated domain.
Make it work for your learner
More support
Use a short square table for real and imaginary multiples before completing the square.
Extension challenge
Choose real coefficients producing roots 4±i and verify your equation.
Verified references · Selected contributions
Standards connections
Subject-content standards
These records identify the part of a subject standard practiced here. Course placement is instructional guidance; the source’s category or band remains authoritative.
Contributes to Common Core standard
HSN.CN.C.7
Common Core · High school · Number and Quantity
Regular high school mathematics standard
Solve real-coefficient quadratics whose roots are nonreal complex numbers.
Read the official standard ↗This lesson contributes selected skills; broader applications and full standard coverage require further instruction.
Verified 2026-11-04. Selected contribution, not full attainment.
